### Video instructions and help with filling out and completing Form 2220 Solutions

**Instructions and Help about Form 2220 Solutions**

Okay so right now ladies and gentlemen give in 58 degrees B equals twelve point eight and a equals eleven point four all right so let's go and draw the triangle like we would any other time so I could say here's a which is at 58 degrees all right here's C and we'll call this one B C we don't know any information for B we know this is twelve point eight and a we know is eleven point four right so automatically ladies and gentlemen you can see that I have side side angle all right when you have side side angle rather than just following your daily tasks that you do every single day I kind of want your ears to perk up and say all right now is a possibility that I have two cases all right because what we need to be able to do is there's a possibility now that I could have multiple triangles alright and here's what here's the case the reason why this isn't really a great triangle I could actually even shorten this up but what I could what I'm trying to show you guys is you could have a triangle that looks like this right couldn't you also just draw the same triangle if you kind of use this as a hinge and it went right there right because we don't know what angle C is right so my angle 11.4 could be here or probably a little bit or we could say eleven point four is here guess see how that's a possibility because we don't know what C is right now all we know is what these two side links are and yes I know my triangle isn't written because this side is much longer than this side and it's shorter but let's get through that but you guys see how I could have two possibilities yes that's like me hinging like that's pretending me like I took this like a hinge on a door and I like I rotated it down to here okay so it's kind of like the pathway of that side so you guys can see there's actually two triangles I could have an OP to I could have a triangle with an OP to C or I could have a triangle with it on a cutesy right so there is a possibility so it's not is it's not as basic it's just hey give me money take it back you know the stuff that we were talking about before so there's a possibility of two different triangles there's also a possibility what if 11.4 looked like that and let's say you know here's this side length is it a possibility that these could not even touch it is let's say if 11.4 is that long and then we end up finding C because we don't know what the length of C is what if C is short all right we'll get through that case right now let's just go and take a look at C I want you guys to understand there's a possibility of either two triangles one triangle or no triangles and this is always going to happen when we look at our side side angle so how does that work because we're going what you just told us to do is just find side side angle and so forth or define your missing angles well let's take a look at it so we have a ratio right we have a over a and we have a side length B so let's create the law of sines so we have 11.4 over the sine of 58 degrees equals 12.8 over the sine of b so we do our same thing we do our cross multiplication and we could say that sine of B is equal to twelve point eight times the sine of 58 degrees all over eleven point four I'm solving for B so I multiply cross multiply to the night divided by eleven point four so I can do 12 point eight times the sine of 58 and then divided by eleven point four so I could say the sine of B is equal to 0.95 to two all right now ladies and gentlemen make sense for that to be an angle right you got to take the inverse sine correct right so you take the inverse sine of your second answer and you get 72 point two one degrees so we say B equals sine inverse of 0.9 0.9 five to two and we could say B equals seventy two point two one degrees okay so here's where it's going to get a little dicey so let's go back to the unit circle all right what I did is I just found the inverse right I apply the inverse and the important thing for you guys to understand about the inverse is if I'm going to look at let's say I have a signed value let's look at the sign value of 1/2 if I say the sign of B equals 1/2 is there one answer or two answers to that there's to it because what is what is is sign equal to one half at PI over six yeah of course it is and it's also equal over here right so if I was going to say sign inverse B of 1/2 we could say B equals PI over six and five PI over six right because your sign is positive in the first and second quadrant so therefore there's two actual answers we could say here it's PI over six which is your reference angle notice these are your reference angles but this angle right here is five PI over six right so does every wonder stand what I'm taking the inverse of my sign I'm my domain I'm going to have two values that are in the first and second quadrant I have.